Answer:
Step-by-step explanation:
slope of line passing through C and D is
[tex]m=\frac{1+2}{8-4} =\frac{3}{4} \\[/tex]
slope of line perpendicular to CD=-4/3
reqd. eq. of line through C(4,-2) is
[tex]y+2=-\frac{4}{3} (x-4)\\3y+6=-4x+16\\4x+3y=10[/tex]
