[tex](h-p))(y) = -y^3-3y^2+7y+5[/tex]
Step-by-step explanation:
Given
[tex]h(y) = -3y^2+5\\p(y) = y^3-7y[/tex]
We have to find the difference of two functions given
So,
[tex](h-p)(y) = h(y) - p(y)\\= (-3y^2+5)-(y^3-7y)\\=-3y^2+5-y^3+7y\\=-y^3-3y^2+7y+5[/tex]
Hence,
[tex](h-p))(y) = -y^3-3y^2+7y+5[/tex]
Keywords: Functions, variables
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