contestada

Two cars leave towns
400

kilometers apart at the same time and travel toward each other. One car's rate is
12

kilometers per hour less than the other's. If they meet in
2

hours, what is the rate of the slower car?

Respuesta :

The speed of slower car is 94 kilometers per hour.

Step-by-step explanation:

Given,

Total distance covered by both cars = 400 km

Time period = 2 hours

Let,

Speed of one car = x

Speed of slower car = x-12

Combined speed = [tex]x+(x-12)=x+x-12=2x-12[/tex]

Distance = Speed*Time

[tex]400=(2x-12)*2\\400=4x-24\\400+24=4x\\424=4x\\4x=424[/tex]

Dividing both sides by 4

[tex]\frac{4x}{4}=\frac{424}{4}\\x=106[/tex]

Speed of slower car = x-12 = 106-12 = 94 km/h

The speed of slower car is 94 kilometers per hour.

Keywords: distance, speed, time

Learn more about speed at:

  • brainly.com/question/12884373
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