A researcher obtains t = 2.35 for a repeated-measures study using a sample of n = 8 participants. Based on this t value, what is the correct decision for a two-tailed test?​

Respuesta :

Answer:

[tex]p_v =2*P(t_{7}>2.35)=2*0.0255=0.051[/tex]  

If we compare the p value and using the significance level given [tex]\alpha=0.05[/tex] we have [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% or 1% of significance we fail to reject the null hypothesis.

Step-by-step explanation:

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided but we can assume it as [tex]\alpha=0.05[/tex]. First we need to calculate the degrees of freedom like this:

[tex]df=n-1=8-1=7[/tex]

The next step would be calculate the p value for this test.  Since is a bilateral test or two tailed test, the p value would be:  

[tex]p_v =2*P(t_{7}>2.35)=2*0.0255=0.051[/tex]  

If we compare the p value and using the significance level given [tex]\alpha=0.05[/tex] we have [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% or 1% of significance we fail to reject the null hypothesis.  

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