Christine collected some toys for a charity. She donated 3/4 of the toys to charity A. Then she donated 1/3 of the remaining toys to charity B. After the two donations, Christine had 10 toys left. How many toys did Christine originally collect?

Respuesta :

Christine originally collected 60 toys

Step-by-step explanation:

Christine collected some toys for a charity.

  • She donated 3/4 of the toys to charity A
  • Then she donated 1/3 of the remaining toys to charity B
  • After the two donations, Christine had 10 toys left

We need to find how many toys Christine originally collected

Assume that Christine originally collected x toys

∵ Christine originally collected x toys

∵ She donated 3/4 of the toys to charity A

∵ [tex]\frac{3}{4}*x[/tex] = [tex]\frac{3}{4}x[/tex]

∴ She donated [tex]\frac{3}{4}x[/tex] to charity A

∴ The remaining = x - [tex]\frac{3}{4}x[/tex]

- Change x to [tex]\frac{4}{4}x[/tex] to make same denominators

∴ The remaining = [tex]\frac{4}{4}x[/tex] - [tex]\frac{3}{4}x[/tex]

∴ The remaining = [tex]\frac{1}{4}x[/tex]

∵ She donated 1/3 of the remaining toys to charity B

∵ The remainder = [tex]\frac{1}{4}x[/tex]

∵ [tex]\frac{1}{3}[/tex] × [tex]\frac{1}{4}x[/tex] = [tex]\frac{1}{12}x[/tex]

∴ She donated [tex]\frac{1}{12}x[/tex] to charity B

∴ The remaining = [tex]\frac{1}{4}x[/tex] - [tex]\frac{1}{12}x[/tex]

- Multiply the first fraction by 3 up and down to make same

  denominators

∴ The remaining = [tex]\frac{3}{12}x[/tex] - [tex]\frac{1}{12}x[/tex]

∴ The remaining = [tex]\frac{2}{12}x[/tex]

- Simplify it by divide up and down by 2

∴ The remaining = [tex]\frac{1}{6}x[/tex]

∵ Christine had 10 toys left

- Equate the remaining by 10

∴ [tex]\frac{1}{6}x[/tex] = 10

- Multiply both sides by 6

x = 60

Christine originally collected 60 toys

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