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Water is pumped steadily out of a flooded basement at a speed of 5.3 m/s through a uniform hose of radius 0.89 cm. The hose passes out through a window to a street ditch 3.2 m above the waterline. What is the power of the pump?

Respuesta :

Answer:

59.885966 W

Explanation:

Mass flow rate of pump is given by

[tex]\frac{\Delta m}{\Delta t}=\rho Av\\\Rightarrow \dot m=1000\times \pi 0.0089^2\times 5.3\\\Rightarrow \dot m=1.318\ kg/s[/tex]

Power is given by

[tex]P=\Delta P+\Delta K\\\Rightarrow P=\dot m gh+\frac{1}{2}\dot mv^2\\\Rightarrow P=1.318\times 9.81\times 3.2+\frac{1}{2}\times 1.318\times 5.3^2\\\Rightarrow P=59.885966\ W[/tex]

As we are using mass flow rate the energy can be taken as power.

So, power of the pump is 59.885966 W

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