Respuesta :
Answer:
[tex]\dfrac{Q_A}{Q_B}=0.031[/tex]
Explanation:
Lets take
Radius of tube A=r
Length of tube A=L
Radius of tube B= r'
Length of tube B=L'
Given that
L = 2 L'
r= 0.5 r'
r' = 2 r
The pressure across tube given as
[tex]\Delta p=\dfrac{8\mu LQ}{\pi R^{4}}[/tex]
[tex]\dfrac{L_AQ_A}{ R_A^{4}}=\dfrac{L_BQ_B}{ R_B^{4}}[/tex]
[tex]\dfrac{Q_A}{Q_B}=\dfrac{R_A^4}{R_B^4}\times \dfrac{L_B}{L_A}[/tex]
[tex]\dfrac{Q_A}{Q_B}=\dfrac{r^4}{(2r)^4}\times \dfrac{L'}{2L'}[/tex]
[tex]\dfrac{Q_A}{Q_B}=\dfrac{1}{16}\times \dfrac{1}{2}[/tex]
[tex]\dfrac{Q_A}{Q_B}=0.031[/tex]
