A steel beam is rotated in a horizontal plane to provide the
centripetal acceleration for training pilots. If a 80 kg pilot
sits 6.7 m from the center of rotation, at what speed (in
m/s) must he rotate to experience a horizontal
centripetal force of 4950 N?

Respuesta :

The speed of the pilot must be 20.4 m/s

Explanation:

The centripetal force acting on the pilot is given by

[tex]F=m\frac{v^2}{r}[/tex]

where

m is the mass of the pilot

v is its linear speed

r is the distance from the center of rotation

In this problem, we have the following data:

m = 80 kg

r = 6.7 m

F = 4950 N is the centripetal force

Solving for v, we find the speed that the pilot should have:

[tex]v=\sqrt{\frac{Fr}{m}}=\sqrt{\frac{(4950)(6.7)}{80}}=20.4 m/s[/tex]

Learn more about circular motion:

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