Electricity is distributed from electrical substations to neighborhoods at 1.5×104 V . This is a 60Hz oscillating (AC) voltage. Neighborhood transformers, seen on utility poles, step this voltage down to the 120V that is delivered to your house.

Part A
How many turns does the primary coil on the transformer have if the secondary coil has 100 turns?
Express your answer using two significant figures. (nprim =?turns)

Part B
No energy is lost in an ideal transformer, so the output power Pout from the secondary coil equals the input power Pin to the primary coil. Suppose a neighborhood transformer delivers 280 A at 120 V. What is the current in the 1.5×104 V line from the substation?
Express your answer using two significant figures.

Respuesta :

Answer:

Np=130 turns, Is=220 A

Explanation:

Part A:

Ns=100 turns

Vp= 1.5*104 V = 156 V

Vs= 120 V

As Np/Ns= Vp/Vs

⇒ Np= [tex]\frac{Vp}{Vs}*Ns[/tex]

⇒Np=[tex]\frac{156*100}{120}[/tex]

Np= 130 turns (It has two significant figures)

Part B

Is=280 A, Vs=120 V, Vp= 1.5*104 V= 156 V

For ideal transformer

Pin=Pout

Ip*Vp= Is*Vs

⇒Ip=([tex]\frac{Is*Vs}{Vp}[/tex])

⇒Ip=[tex]\frac{280*120}{156}[/tex]

⇒Ip=215.4 A

to represent it as two significant figures we will write as

Ip=220 A

The primary coil on the transformer have 12500 coils and the primary current is 2.24 A

What is a transformer?

A transformer is an electrical device that steps up or steps down voltage.

The turn ratio = primary voltage / secondary voltage

Hence:

Turns ratio = 1.5 * 10⁴ / 120 = 125

If the secondary coil has 100 turns:

Primary coil = 125 * 100 turns = 12500

Efficiency = Output / input

Hence:

1 = (280 * 120) / (1.5 * 10⁴ * I)

I = 2.24 A

The primary coil on the transformer have 12500 coils and the primary current is 2.24 A

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