Respuesta :
Answer:
When SO₂ is mixed with O₂ in a container, the initial rate of the forward reaction (production of SO₃) is faster than the initial rate of the reverse reaction (production of SO₂).
At equilibrium the concentration of SO₂ will no longer be changing.
Explanation:
Let's consider the following reaction.
2 SO₂(g) + O₂(g) ⇌ 2 SO₃(g)
Which of the following are true statements about this reaction?
When SO₂ is mixed with O₂ in a container, the initial rate of the forward reaction (production of SO₃) is faster than the initial rate of the reverse reaction (production of SO₂). TRUE. Initially, when there is no SO₃ in the container, the rate of production of SO₂ is zero.
As SO₂ is used up and SO₃ accumulates, the rate of the forward reaction increases and the rate of the reverse reaction decreases. FALSE. As the equilibrium is reached, the rate of the forward reaction decreases and the rate of the reverse reaction increases.
At equilibrium the rate of production of SO₃ reaches zero. FALSE. At equilibrium, the rate of production of SO₃ is equal to the rate of production of SO₂, which is why the concentrations remain constant.
At equilibrium the concentration of SO₂ will no longer be changing. TRUE. At equilibrium, the concentrations of reactants and products remain constant.