Answer: 3.675 moles of [tex]N_2[/tex] gas
Explanation:
Decomposition of sodium azide is shown by equation below:
[tex]2NaN_3\rightarrow 2Na+3N_2[/tex]
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
[tex]\text{Number of moles of sodium azide}=\frac{159.2g}{65g/mol}=2.450moles[/tex]
According to stoichiometry:
2 moles of [tex]NaN_3[/tex] produce 3 moles of [tex]N_2[/tex]
Thus 2.450 moles of [tex]NaN_3[/tex] will produce=[tex]\frac{3}{2}\times 2.450=3.675[/tex] moles of [tex]N_2[/tex]
Thus 3.675 moles of [tex]N_2[/tex] gas are produced when 159.2 g [tex]NaN_3[/tex] decomposes.
