Answer:
Tension, T = 95 N
Explanation:
Given that,
Mass of the rope, m = 1.8 kg
length of the rope, L = 11.1 m
Frequency of the first harmonic, f = 1.09 Hz
The fundamental frequency in case of string is given by :
[tex]f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}[/tex]
[tex]\mu=\dfrac{m}{L}=\dfrac{1.8}{11.1}=0.162\ kg/m[/tex]
[tex]T=4L^2f^2\mu[/tex]
[tex]T=4\times (11.1)^2\times (1.09)^2\times 0.162[/tex] `
T = 94.85 N
or
T = 95 N
So, the tension of this rope is 95 N. Hence, this is the required solution.
