Answer:[tex]1.94 m/s^2[/tex]
Explanation:
Given
inclination [tex]\theta =30.6^{\circ}[/tex]
Coefficient of kinetic Friction [tex]\mu =0.36[/tex]
Forces on crate is
[tex]mg\sin \theta -f_r=ma[/tex]
[tex]f_r=\mu mg\cos \theta [/tex]
[tex]mg\sin \theta -\mu mg \cos \theta =ma[/tex]
[tex]a=g\sin \theta -\mu g\cos \theta [/tex]
[tex]a=1.94 m/s^2[/tex] Â