Answer:
The area of the field is [tex]660 m^{2}[/tex]
Step-by-step explanation:
Given that the measurements are
AD = 40 m, CD = 17 m, BC = 48 m
In the given figure, construct Line perpendicular from D to side CB.
So the formed figure is rectangle and triangle.
The triangle being right angled, applying pythagoras theorm ,
[tex]17^{2} = 8^{2} + x^{2}[/tex]
Thus, [tex]x^{2} = 289 - 64 = 225[/tex]
[tex]x = 15 m[/tex]
thus, AB = 15 m ( rectangle opposite sides are equal)
Thus, Area of trapezium is,
[tex]A = (\frac{1}{2})(Sum of parralle sides)(distance between them)[/tex]
[tex]A = (\frac{1}{2})(40 + 48)(15)[/tex]
A = [tex]660 m^{2}[/tex]
