Answer:P(8)=1/10
The events are mutually exclusive so,
P(4 or 6 or 8)=P(4)+P(6)+P(8)=1/10+1/10+1/10=3/10.
Based on the probability of picking those cards individually, the probability that you will pick 3, 6, or 7 is 3/10.
You can either pick any one of them and not all three so these events are mutually exclusive.
The probability is:
= Prob. of picking 3 + Prob. of picking 6 + Prob. of picking 7
= 1/10 + 1/10 + 1/10
= 3/10
Find out more on probability at https://brainly.com/question/24756209.
