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What is the capillary rise of ethanol in a glass tube with a 0.1 mm radius if the surface tension of ethanol is 0.032Jm2 and the density of ethanol is 0.71gcm3? Assume that the contact angle of ethanol in a glass tube is 0 degrees.

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igeclement43

Answer: The capillary rise(h) in the glass tube is = 0.009m

Explanation:

Using the equation

h = 2Tcosθ/rpg

Given

Contact angle, θ = Zero

h = height of the glass tube=?

T = surface tension = [tex]0.032J/m^2[/tex]

r = radius of the tube = 0.1mm =0.0001m

p= density of ethanol = [tex]0.71g/cm^3[/tex]

g= [tex]9.8m/s^2[/tex]

h = [tex](2 * 0.032 * cos 0)/( 710*9.8*0.0001)[/tex]

h= 0.09m

Therefore the capillary rise in the tube is 0.09m

yoimeatingthisc

Answer:

0.092

Explanation:

height=2Tcosθrpg2(0.032Jm2)(710kgm3)(9.8ms2)(1×10−4 m)=0.092 m

Notice that constants in the mathematical formula are exact, so they do not constrain the number of significant figures.

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