Answer:
+0.52m
Explanation:
The force applied by the archer is directly proportional to the displacement of the bow string provided the elastic limit of the string is not exceeded.
[tex]F_{applied}[/tex] = kx
k = string constant
x = string extension
[tex]x = \frac{F_{applied} }{k}[/tex]
[tex]x = \frac{+280N} }{540N/m}[/tex]
[tex]x = \frac{F_{applied} }{k}[/tex]
x = +0.5185m
x = +0.52m
The displacement of the bow string is +0.52m
