Answer:
Tension, T = 547.58 N
Explanation:
It can be assumed that,
Mass of the string, m = 8.75 g
Length of the string, l = 70 cm = 0.7 m
Wavelength of produced sound, [tex]\lambda=0.767\ m[/tex]
Speed of sound, v = 344 m/s
We know that second overtone is the third harmonic. The frequency in second overtone is given by :
[tex]f=\dfrac{v}{3\lambda}[/tex]
[tex]f=\dfrac{344}{3\times 0.767}[/tex]
f = 149.5 Hz
The frequency in terms of length is given by :
[tex]f=\dfrac{1}{2l}\sqrt{\dfrac{T}{m/l}}[/tex]
[tex]T=4f^2l^2\dfrac{m}{l}[/tex]
[tex]T=4f^2lm[/tex]
[tex]T=4\times (149.5)^2\times 0.7\times 8.75\times 10^{-3}[/tex]
T = 547.58 N
So, the tension in the string is 547.58 N. Hence, this is the required solution.