Answer:
(a) 1.60 × 10⁻⁹ mm³/cell
(b) 2 × 10⁻⁴ L
Explanation:
The volume of a certain bacterial cell is 1.60 μm³. Give your answers in scientific notation.
(a) What is its volume in cubic millimeters (mm³)?
The required conversion factors are:
[tex]\frac{1.60\mu m^{3} }{cell} .(\frac{1m}{10^{6} \mu m})^{3} .(\frac{10^{3}mm }{1m} )^{3} =1.60\times 10^{-9} mm^{3} /cell[/tex]
(b) What is the volume of (exactly) 1 × 10⁸ cells in liters (L)?
The required conversion factors are:
[tex]1\times 10^{8} cell \times \frac{1.60\times 10^{-9} mm^{3}}{cell} \times \frac{1mL}{1mm^{3} } \times \frac{1L}{10^{3}mL } =2 \times 10^{-4} L[/tex]
