Answer:18.31 s
Explanation:
Given
hole is h=0.9 m below the water surface
area of of hole [tex]A=1.30 cm^2[/tex]
Q=10 L
velocity of Flow
[tex]v=\sqrt{2gh}[/tex]
[tex]v=\sqrt{2\times 9.8\times 0.9}[/tex]
[tex]v=\sqrt{17.64}[/tex]
[tex]v=4.2 m/s[/tex]
Rate of flow is given by
[tex]\dot{Q}=A\cdot v[/tex]
[tex]\frac{Q}{t}=A\cdot v[/tex]
[tex]\frac{10\times 10^{-3}}{t}=1.30\times 10^{-4}\cdot 4.2[/tex]
[tex]t=\frac{10\times 10}{5.46}[/tex]
[tex]t=18.31 s[/tex]