Respuesta :
What is the value of a^2 + 3b ÷ c - 2d when a = 3, b = 8, c = 2, and d = 5
a. 8
b. 12
c. 10
d. 11
Answer:
Option D
The value of a^2 + 3b ÷ c - 2d when a = 3, b = 8, c = 2, and d = 5 is 11
Solution:
Given that expression is a^2 + 3b ÷ c - 2d
We can use BODMAS rule to solve this expression
BODMAS means brackets, order, division, multiplication, addition and subtraction
According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right.
Substitute a = 3, b = 8, c = 2, and d = 5
[tex]a^2 + 3b \div c - 2d = 3^2 + 3(8) \div 2 -10[/tex]
Let us first solve the terms in brackets as per BODMAS rule
[tex]9 + 24 \div 2 -10[/tex]
Now perform division as per BODMAS
[tex]9 + 12 -10[/tex]
Now peform addition operation
[tex]21 - 10[/tex]
Now peform subtraction operation
21 -10 = 11
Thus the value of a^2 + 3b ÷ c - 2d when a = 3, b = 8, c = 2, and d = 5 is 11
