Respuesta :

[tex]\bf \textit{circumference of a circle}\\\\ C=\pi d~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ C=907.46 \end{cases}\implies 907.46=\pi d\implies \cfrac{907.46}{\pi }=d \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 288.85\approx d~\hfill[/tex]

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