Respuesta :
Answer:
W= 4.89 KJ
Explanation:
Lets take
temperature of hot water T₁ = 100⁰C
T₁ = 373 K
Temperature of cold ice T₂= 0⁰C
T₂ = 273 K
The latent heat of ice LH= 334 KJ
The heat rejected by the engine Q= m .LH
Q₂= 0.04 x 334
Q₂= 13.36 KJ
Heat gain by engine = Q₁
For Carnot engine
[tex]Q_1=\dfrac{T_1}{T_2}Q_2[/tex]
[tex]Q_1=\dfrac{373}{273}\times 13.36[/tex]
Q₁ = 18.25 KJ
The work W= Q₁ - Q₂
W= 18.25 - 13.36 KJ
W= 4.89 KJ
Answer:
W = 4893.77 J
Explanation:
given,
mass of the ice = 0.04 Kg
time of operation = 5 minutes
Heat delivered =
[tex]Q_c = m_c \Delta H_f[/tex]
Δ H_f is latent heat of fusion of ice = 334 x 10³ J/Kg
[tex]Q_c = 0.04 \times 334 \times 10^3[/tex]
[tex]Q_c = 13360\ J[/tex]
Work done
W = Q_H - Q_C
[tex]Q_H= (\dfrac{T_H}{T_C})Q_C[/tex]
[tex]W= (\dfrac{T_H}{T_C}-1)Q_C[/tex]
[tex]W= (\dfrac{373}{273}-1)\times 13360[/tex]
W = 4893.77 J
