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A jogger hears a car alarm and decides to investigate. While running toward the car, she hears an alarm frequency of 872.10 Hz. After passing the car, she hears the alarm at a frequency of 851.10 Hz. If the speed of sound is 343 m/s. 1) Calculate the speed of the jogger.

Respuesta :

Answer:

v = 4.18 m/s

Explanation:

given,

frequency of the alarm = 872.10 Hz

after passing car frequency she hear = 851.10 Hz

Speed of sound = 343 m/s

speed of the jogger = ?

speed of the

[tex]v_f = \dfrac{872.10-851.10}{2}[/tex]

[tex]v_f =10.5\ Hz[/tex]

v_o = 872.1 - 10.5

[tex]V_0 = 861.6\ Hz[/tex]

The speed of jogger

[tex]v = \dfrac{v_1 \times 343}{v_0}-343[/tex]

[tex]v = \dfrac{872.1 \times 343}{861.6}-343[/tex]

v = 4.18 m/s

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