contestada

Calculate the rate of some reaction that obeys Avrami kinetics, assuming that the constants n and k have values of 2.0 and 0.006, respectively, for time expressed in seconds.

Respuesta :

Khoso123

Answer:

rate=0.093 s⁻¹

Explanation:

Given Data

n=2.0

k=0.006

assume y=0.5 because it is not given in question

rate=?

Solution

As we know that

[tex]e^{-kt^{n} } =1-y\\t^{n}=-\frac{ln(1-y)}{k}\\  t=-(\frac{ln(1-y)}{k} )^{\frac{1}{n} }\\ t=-(\frac{ln(1-0.5)}{0.006} )^{\frac{1}{2} }\\t=10.74 seconds\\rate=\frac{1}{t}\\ rate=\frac{1}{10.74} \\rate=0.093s^{-1}[/tex]

batolisis

The rate of some reaction that obeys Avrami Kinetics is :  0.093 s⁻¹

Given data:

n = 2.0

k = 0.006

let's assume y = 0.5

Determine the rate of some reaction that obeys Avrami kinetics

applying the equation below

[tex]e^{-kt^{n} } = 1 - y[/tex] ------ ( 1 )

solve for t

t = [tex]- (\frac{In(1-y)}{k} )^{\frac{1}{n} }[/tex]  ------- ( 2 )

where : n = 2, y = 0.5,  k = 0.006,  

Insert values into equation ( 2 )

t = 10.74 secs

Rate = 1 / t

        = 1 / 10.74

        = 0.093 s⁻¹

Hence we can conclude that The rate of reaction that obeys Avrami Kinetics is : 0.093 s⁻¹.

Learn more about rate of reaction : https://brainly.com/question/25724512

Otras preguntas

Q&A Education