Respuesta :
Answer :
The equilibrium favors NO and [tex]Br_2[/tex].
(1) The value of equilibrium constant for this reaction is, 76.9
(2) The value of equilibrium constant for this reaction is, 8.77
Explanation:
The given chemical equation is:
[tex]2NO(g)+Br_2(g)\rightarrow 2NOBr(g)[/tex]
The value of equilibrium constant for the above equation is [tex]K_c=1.3\times 10^{-2}[/tex].
The value of [tex]K_c<1[/tex] that means equilibrium lies to the left side. Thus, the equilibrium favors NO and [tex]Br_2[/tex].
We need to calculate the equilibrium constant for the given equation of above chemical equation, which is:
(1) [tex]2NOBr(g)\rightarrow 2NO(g)+Br_2(g)[/tex]
The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.
The value of equilibrium constant for reverse reaction is:
[tex]K_{c_1}=\frac{1}{K_c}[/tex]
[tex]K_{c_1}=\frac{1}{1.3\times 10^{-2}}=76.9[/tex]
Thus, the value of equilibrium constant for this reaction is, 76.9
(2) [tex]NOBr(g)\rightarrow NO(g)+\frac{1}{2}Br_2(g)[/tex]
The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.
If the equation is multiplied by a factor of '1/2', the equilibrium constant of the reverse reaction will be the 1/2 power of the equilibrium constant of initial reaction.
The value of equilibrium constant for reverse reaction is:
[tex]K_{c_2}=(\frac{1}{K_c})^{1/2}[/tex]
[tex]K_{c_2}=(\frac{1}{1.3\times 10^{-2}})^{1/2}=8.77[/tex]
Thus, the value of equilibrium constant for this reaction is, 8.77
The equilibrium constant is a numerical value that shows the extent of conversion of reactants to products.
The equilibrium constant is a numerical value that shows the extent of conversion of reactants to products. We initially have the reaction;
2NO(g)+Br2(g)телтем==2NOBr(g) having Kc = 1.3├Ч10тИТ2
For the reaction; 2NOBr(g)телтем==2NO(g)+Br2(g), it follows that Kc =(1.3├Ч10тИТ2)^-1 = 76.9. For the second reaction; NOBr(g)телтем==NO(g) + 1/2Br2(g), we can see that it is half of the other reaction hence Kc =(76.9)^ 1/2 = 8.77.
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