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An atom of 110I has a mass of 109.935060 amu. Calculate its binding energy per MOLE in kJ. Enter your answer in exponential format (1.23E4) with 3 significant figures and no units. Use the masses: mass of 1H atom = 1.007825 amu mass of a neutron = 1.008665 amu 1 amu = 931.5 Mev c = 2.99792 x 108 m/s

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abiolaraymond1995

Answer:

E= 2.72E8 KJ  (to 3.S.f)

Explanation:

Binding energy is the reason for the slight difference between masses of nucleus components to the actual masses of nucleus.

Binding energy (E) = mc^{2}

where m is the mass defect. c

           c is the speed of light .

Mass defect is calculated as follows.

iodine element has a structure

\left \{ {{y=110} \atop {x=53}} \right I

mass number(sum of proton +neutron) = 110

atomic number (proton only) = 53

number of neutrons = mass number - atomic number = 110-53 = 57

we will calculate the mass of protons and neutron in the atom.

Proton = 1.007825amu * 53 = 53.414725amu

neutron = 1.008665amu * 57 = 57.493905

actual mass of nucleus = 109.935060amu

mass defect= sum of mass of protons and neutrons - actual mass of nucleus

                  = 53.414725amu + 57.493905amu - 109.935060amu

               m   =0.97357amu.

E= mc^{2}  

 1amu = 931.5Mev

E=   0.97357 * 931.5 * 2.99792*10^{8}

E=2718.755053*10^{8}

E= 2.718 * 10^{11}J

E= 2.72E8 KJ  (to 3.S.f)

E= 2.72E8

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