Answer:
[tex]\large\boxed{\dfrac{y-1}{7}}[/tex]
Step-by-step explanation:
[tex]\dfrac{y^2-2y+1}{7}\div(y-1)=\dfrac{y^2-y-y+1}{7}\div(y-1)\\\\=\dfrac{y(y-1)-1(y-1)}{7}\cdot\dfrac{1}{y-1}=\dfrac{(y-1)(y-1)}{7}\cdot\dfrac{1}{y-1}\\\\\text{cancel}\ (y-1)\\\\=\dfrac{y-1}{7}\cdot\dfrac{1}{1}=\dfrac{y-1}{7}[/tex]
