From highest to lowest maximum kinetic energy:
Cesium (1.0 eV)
Potassium (0.8 eV)
Aluminium, Beryllium, Magnesium and platinum (for all of them, no electrons are emitted)
Explanation:
The photoelectric effect occurs when electromagnetic radiation hits the surface of the metal and, if the photons of the radiation have enough energy, they free electrons from the metal's surface.
The equation describing the photoelectric effect is:
[tex]hf = \phi +K_{max}[/tex]
where
[tex]hf[/tex] is the energy of the incoming photons, with [tex]h[/tex] being the Planck's constant and [tex]f[/tex] being the frequency of the photons
[tex]\phi[/tex] is the work function of the metal, which is the minimum energy that the photons must have in order to be able to liberate photoelectrons from the metal
[tex]K_{max}[/tex] is the maximum kinetic energy of the photoelectrons
The equation can be rewritten as
[tex]K_{max} = hf-\phi[/tex] (1)
In this problem we have:
[tex]hf=3.10 eV[/tex] is the energy of the incoming photons
Now for each metal we have:
A) alumninum: [tex]\phi = 4.1 eV[/tex] --> the work function is higher than the energy of the photons, so no electrons are emitted
B) platinum [tex]\phi=6.4 eV[/tex] --> the work function is higher than the energy of the photons, so no electrons are emitted
C) cesium [tex]\phi=2.1 eV[/tex], so [tex]K_{max}=3.1 eV - 2.1 eV = 1.0 eV[/tex]
D) beryllium [tex]\phi = 5.0 eV[/tex] --> the work function is higher than the energy of the photons, so no electrons are emitted
E) magnesium [tex]\phi=3.7 eV[/tex] --> the work function is higher than the energy of the photons, so no electrons are emitted
F) potassium [tex]\phi = 2.3 eV[/tex], so [tex]K_{max}=3.1 eV - 2.3 eV = 0.8 eV[/tex]
Therefore, ranking from highest to lowest maximum kinetic energy:
Cesium (1.0 eV)
Potassium (0.8 eV)
Aluminium, Beryllium, Magnesium and platinum (for all of them, no electrons are emitted)
Learn more about photoelectric effect:
brainly.com/question/10015690
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