Respuesta :
Taking into account the reaction stoichiometry, the correct answer is option B): 9 grams of aluminum are necessary to produce 0.50 mol of hydrogen gas at 25°C and 1.0 atm.
The balanced reaccion is:
6 HCl + 2 Al → 2 AlCl₃ + 3 H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- HCl: 6 moles
- Al: 2 moles
- AlCl₃: 2 moles
- H₂: 3 moles
The atomic mass of aluminum is 27 g/mole. Then, by reaction stoichiometry, the following mass quantity of aluminum participates in the reaction:
[tex]2 molesx\frac{27 grams}{1 mole} = 54 grams[/tex]
Then you can apply the following rule of three: if by reaction stoichiometry 3 moles of H₂ are formed from 54 grams of Al, 0.50 moles of H₂ are formed from how much mass of Al?
[tex]mass of Al=\frac{0.50 moles ofH_{2}x54 grams of Al }{3 moles of H_{2} }[/tex]
mass of Al= 9 grams
In summary, the correct answer is option B): 9 grams of aluminum are necessary to produce 0.50 mol of hydrogen gas at 25°C and 1.0 atm.
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The moles can be calculated by the ratio of mass of given substance and the molar mass of that substance. The 9 grams of aluminum is necessary to produce 0.50 moles of hydrogen gas.
Give that,
- Temperature = 25-dgree celcius
- Molar mass = 27 g/mole
- Pressure = 1 atm
The chemical reaction between HCl and aluminum can be written as:
[tex]\text {6 HCl + 2 Al} \rightarrow \text{ 2 AlCl}_3 + \text{3 H}_2[/tex]
By reaction stoichiometry, the number of moles of each compound participating the reaction are:
- Hydrochloric acid: 6 moles
- Aluminum: 2 moles
- Aluminum chloride: 2 moles
- Hydrogen: 3 moles
Now, mass of aluminum produced in the reaction, such as:
- [tex]\text {2 moles} \times\dfrac{27\text{gram}}{1\text{mole}}& = 54\;\text{gram}[/tex]
Now, using the rules of stochiometric reaction, we get:
- [tex]\text{mass of Al}&=\dfrac{0.50\;\text{moles of H}_2\times54\;\text {grams of Al}}{3\text{moles of H}_2}[/tex]
- Mass of Al = 9 grams.
Therefore, the amount of aluminum produced by 0.50 moles of hydrogen at 25-degree celcius and 1 atm is 9 grams.
To know more about stoichiometric relations, refer to the following link:
https://brainly.com/question/15099797?referrer=searchResults
