A coil of area 0.2 m2 and total resistance 100 Ω is rotated at a rate of 60 rev/s. Its axis of rotation is perpendicular to a 0.5 T magnetic field. How many turns are in the coil if energy is delivered to it at a maximum rate of 1420 W?

Respuesta :

The concept necessary to solve this problem is the mathematical definition of the electromotive force or induced voltage. Theoretically the electromotive force is the electrical action produced by a non-electrical source. Mathematically it can be expressed as

[tex]\epsilon = NBA\omega[/tex]

Where

N = Number of loops

B = Magnetic Field

A = Cross-sectional Area

[tex]\omega =[/tex] Angular velocity

Re-arrange to find N,

[tex]N = \frac{\epsilon}{BA\omega}[/tex]

In parallel, we can also consider the rate of energy change expressed in terms of the induced voltage, that is,

[tex]P = \frac{\epsilon^2}{R}[/tex]

Where

R = Resistance

The previous equation can be expressed as

[tex]\epsilon=\sqrt{PR}[/tex]

Equating the two expression we have

[tex]N = \frac{\sqrt{PR}}{BA\omega}[/tex]

Replacing with our values we have that

[tex]N = \frac{\sqrt{(1420)(100)}}{(0.5)(0.2)(60*2\pi)}[/tex]

[tex]N=9.9957 \approx 10[/tex]

Therefore the number of turns are 10.

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