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If y varies as x and y=5 when x=8 find y when x=9 enter your answer in a decimal ( rounded to 2 decimals)

Respuesta :

Answer:

[tex]y=5.63[/tex]

Step-by-step explanation:

Given

[tex]y[/tex] varies directly with [tex]x[/tex]

This means

[tex]y[/tex] ∝ [tex]x[/tex]

This can be written as:

[tex]y=k\ x[/tex]

where [tex]k[/tex] is the constant of proportionality.

We know that when [tex]x=8[/tex] then [tex]y=5[/tex]. Using this we can find value of [tex]k[/tex].

so, we have

[tex]5=k(8)[/tex]

Dividing both sides by 8 to isolate [tex]k[/tex].

[tex]\frac{5}{8}=\frac{k(8)}{8}[/tex]

∴ [tex]k=\frac{5}{8}[/tex]

when [tex]x=9[/tex] then [tex]y[/tex] will be

[tex]y=\frac{5}{8}\times 9[/tex]

∴ [tex]y=\frac{45}{8}\approx 5.63[/tex] (Answer)

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