At a particular restaurant, each onion ring has 40 calories and each pizza roll has 50 calories. A combination meal with onion rings and pizza rolls has a total of 23 onion rings and pizza rolls altogether and contains 1010 calories. Write a system of equations that could be used to determine the number of onion rings in the combination meal and the number of pizza rolls in the combination meal. Define the variables that you use to write the system.

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jitumahi76 jitumahi76 · Answer 1 · 2019-12-12T06:44:08+01:00

Answer:

Hence the system of equation are [tex]x + y =23 \ \ \ and \ \ \ 4x+5y=101[/tex].

Also 14 onion rings and 9 pizza rolls are used in combination meal.

Step-by-step explanation:

Let the number of onion rings in the combination meal be x

and let the number of pizza rolls in the combination meal be y

Given;

Combination meal consist of 23 onion rings and pizza rolls

hence [tex]x + y =23 \ \ \ \ \ equation \ 1[/tex]

Also given;

each onion ring has = 40 calories

each pizza roll has = 50 calories

Combination meal consist = 1010 calories

hence we can say that;

[tex]40x+50y=1010[/tex]

Dividing 10 on both side using division property we get;

[tex]\frac{40x}{10}+\frac{50y}{10}=\frac{1010}{10}\\\\4x+5y=101 \ \ \ \ \ equation \ 2[/tex]

Multiplying equation 1 with 5 using multiplication Property we get;

[tex]5x+5y= 115 \ \ \ \ \ \ equation \ 3[/tex]

Subtracting equation 2 from equation 3 we get;

[tex]\frac{40x}{10}+\frac{50y}{10}=\frac{1010}{10}\\\\[tex](5x+5y)-(4x+5y)= 115-101\\5x+5y-4x-5y=14\\x = 14[/tex]

Hence x =14 we will substitute this value in equation 1 we get;

[tex]x+y=23\\14+y =23\\y =23 -14\\y= 9[/tex]

Hence the system of equation are [tex]x + y =23 \ \ \ and \ \ \ 4x+5y=101[/tex].

Also 14 onion rings and 9 pizza rolls are used in combination meal.