Answer:
The bikers speed at the top of other hill is 25.82 m/s.
Explanation:
Considering the biker is riding on a frictionless surface.
∴ There is no non-conservative or external force acting on the biker.
Hence we can conserve the energy of biker and bike as a system.
Let,
[tex]h_{1}[/tex] = 44m
[tex]h_{2}[/tex] = 10m
Since the biker starts from rest , his initial speed [tex]v_{1}[/tex] = 0 m/s
Let final speed of the bike at the top of other hill be [tex]v_{2}[/tex].
∴ Initial Energy (at the top of 44m hill) = [tex]mgh_{1}[/tex]
Final Energy (at the top of 10m hill) = [tex]mgh_{2} + \frac{1}{2}mv_{2} ^{2}[/tex].
Conserving both the energies , we get
[tex]mgh_{1}[/tex] = [tex]mgh_{2} + \frac{1}{2}mv_{2} ^{2}[/tex]
∴ [tex]v_{2} = \sqrt{2g(h_{1}-h_{2} )}[/tex]
Substituting the values for g , [tex]h_{1}[/tex] , [tex]h_{2}[/tex] , we get
[tex]v_{2}[/tex] = 25.82 m/s
