To develop this problem we simply have to perform conversions per second to know the amount of fission that are made. A simple mathematical calculation that starts from:
[tex]P = 915W[/tex]
Watts is the energy invested over time therefore
[tex]P = 915\frac{J}{s}[/tex]
According to the statement there is a release per second of 200MeV so the number of Fisions per second would be subject to
[tex]#_{fissions} = \frac{915J/s}{200*10^6eV(\frac{1.6*10^{-19}J}{1eV})}[/tex]
[tex]#_{fissions} = 28593.75*10^{9}s^{-1}[/tex]
Therefore there are 28593.75*10^{9} Fissions per second.
