The Correct option is D). y=1x+1 And y=2x+2
Step-by-step explanation:
The equation of a line is given as y=mx+c.
where m=slope of line and c=y intercept
The slope of line is given as m=[tex]\frac{(Y2-Y1)}{(X2-X1)}[/tex]
Solving for Redline:
From the given graph, redline passes through (-1,0) and (0,1)
The slope of Redline is m=[tex]\frac{(Y2-Y1)}{(X2-X1)}[/tex]
The slope of Redline is m=[tex]\frac{(1-0)}{(0-(-1))}[/tex]
The slope of Redline is m=(1)
And Y-intercept is 1
The equation of a Redline is given as y=1x+1
Solving for Blue-line:
From the given graph, Blue-line passes through (-1,0) and (0,2)
The slope of Blue-line is m=[tex]\frac{(Y2-Y1)}{(X2-X1)}[/tex]
The slope of Blue-line is m=[tex]\frac{(2-0)}{(0-(-1))}[/tex]
The slope of Blue-line is m=(2)
And Y-intercept is 2
The equation of a Blue-line is given as y=2x+2
The Correct option is D). y=1x+1 And y=2x+2
