Answer:
[tex]x_1=5.70\\\\x_2=-0.70[/tex]
Step-by-step explanation:
Given a Quadratic equation in the form:
[tex]ax^2+bx+c=0[/tex]
You can use the Quadratic formula to solve it:
[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]
In this case you have the following Quadratic equation:
[tex]x^2-5x-4=0[/tex]
You can identify that:
[tex]a=1\\b=-5\\c=-4[/tex]
Then, you can substitute values into the Quadratic formula:
[tex]x=\frac{-(-5)\±\sqrt{(-5)^2-4(1)(-4)}}{2(1)}[/tex]
Evaluating, you get the following solutions:
[tex]x_1=5.70\\\\x_2=-0.70[/tex]
