The work done by Jose is 600 J
Explanation:
The work done when moving an object is given by
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this problem, we have
F = 60 N is the force applied by Jose
d = 10 m is the displacement of the object
[tex]\theta=0[/tex], assuming that Jose applies a vertical force, in the same direction as the displacement
Substituting, we find
[tex]W=(60)(10)(cos 0)=600 J[/tex]
Learn more about work:
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