A gardener is planting two types of trees:

Type A is 9 feet tall and grows at a rate of 2 inches per year.

Type B is 8 feet tall and grows at a rate of 5 inches per year.

Algebraically determine exactly how many years it will take for these trees to be the same height.

Respuesta :

It would take exactly 4 years for these trees to be the same height.

Step-by-step explanation:

Given,

Height of Tree A = 9 feet

1 feet = 12 inches

9 feet = 9*12 = 108 inches

Growth rate = 2 inches per year

Let,

y be the number of years.

A(y)= 108 + 2y

Height of Tree B = 8 feet

8 feet = 8*12 = 96 inches

Growth rate = 5 inches per year

B(y)=96+5y

In case of same height;

A(y)=B(y)

[tex]108+2y=96+5y\\108-96=5y-2y\\12=3y\\3y=12[/tex]

Dividing both sides by 3

[tex]\frac{3y}{3}=\frac{12}{3}\\y=4[/tex]

It would take exactly 4 years for these trees to be the same height.

Keywords: functions, division

Learn more about functions at:

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