The solution of the system of equations is:
x=0 and y = 8
Step-by-step explanation:
Given equations are:
[tex]-5x+5y = 40\ \ \ Eqn\ 1\\4x+3y = 24\ \ \ Eqn\ 2[/tex]
Multiplying eqn 1 by 4
[tex]-20x+20y = 160\ \ \ Eqn\ 3[/tex]
Multiplying equation 2 by 5
[tex]20x+15y = 120\ \ \ Eqn\ 4[/tex]
Adding equation 3 and 4
[tex]-20x+20y +20x+15y = 160+120\\35y = 280[/tex]
dividing both sides by 35
[tex]\frac{35y}{35} = \frac{280}{35}\\y = 8[/tex]
Putting y=8 in equation 1
[tex]-5x+5(8) = 40\\-5x+40 = 40\\-5x = 40-40\\-5x = 0\\x = 0[/tex]
The solution of the system of equations is:
x=0 and y = 8
Keywords: Linear equations, Solution
Learn more about linear equations at:
- brainly.com/question/12884373
- brainly.com/question/12896802
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