Answer
given,
mass skateboard = 5 Kg
length on the horizontal road = 2 m
maximum speed she can run= 8 m/s
mass of girl = 50 Kg
conservation of momentum
M V = (M+m)v
50 x 8 = (50 + 5)v
400 = (55)v
v = 7.27 m/s
using conservation of momentum
[tex]m g h = \dfrac{1}{2} m v^2[/tex]
[tex]h = \dfrac{v^2}{2g}[/tex]
[tex]h = \dfrac{7.27^2}{2\times 9.8}[/tex]
h = 2.69 m
no, she will not be able to reach the height of 3 m
