Answer:
The moment of inertia of this sphere is [tex]0.0929\ kg-m^2[/tex].
Explanation:
It is given that,
Mass of the sphere, m = 4.8 kg
Radius of the sphere, r = 22 cm = 0.22 m
Tangential force, F = 11.2 N
The moment of inertia of the uniform sphere is given by :
[tex]I=\dfrac{2}{5}mr^2[/tex]
[tex]I=\dfrac{2}{5}\times 4.8\ kg\times (0.22\ m)^2[/tex]
[tex]I=0.0929\ kg-m^2[/tex]
So, the moment of inertia of this sphere is [tex]0.0929\ kg-m^2[/tex]. Hence, this is the required solution.
