Answer:
Work done by the force of friction is 305.96 joules.
Explanation:
It is given that,
Mass of the child, m = 21 kg
Height of the slide, h = 1.5 m
Speed of the child at the bottom, v = 0.51 m/s
Let W is the work done by the force of friction on the child. It can be calculated using the work energy theorem as :
[tex]mgh+W=\dfrac{1}{2}mv^2[/tex]
[tex]W=\dfrac{1}{2}mv^2-mgh[/tex]
[tex]W=m(\dfrac{1}{2}v^2-gh)[/tex]
[tex]W=21\times (\dfrac{1}{2}(0.51)^2-9.8\times 1.5)[/tex]
W = -305.96 joules
So, the work done by the force of friction on the child is 305.96 joules. Hence, this is the required solution.
