The net torque is [tex]28.8 N \cdot m[/tex] in the counterclockwise direction
Explanation:
In order to find the net torque, we have to calculate the clockwise torque and the counterclockwise torque, and then evaluate their difference.
The clockwise torque is given by:
[tex]\tau_C = F_C r[/tex]
where
[tex]F_C = 43 N[/tex] is the force applied in the clockwise direction
r = 1.2 m is the distance between the point of application of the force and the axis of rotation (it is equal to half the diameter)
Substituting,
[tex]\tau_C = (43)(1.2)=51.6 N \cdot m[/tex]
Similarly, the counterclockwise torque is given by:
[tex]\tau_A = F_A r[/tex]
where
[tex]F_A = 67 N[/tex] is the force applied in the counterclockwise direction
r = 1.2 m
Substituting,
[tex]\tau_A = (67)(1.2)=80.4 N \cdot m[/tex]
Therefore, the net torque on the wheel is
[tex]\tau = \tau_A - \tau_C = 80.4-51.6=28.8 N \cdot m[/tex]
In the counterclockwise direction, since the counterclockwise moment is larger than the clockwise one.
Learn more about torque:
brainly.com/question/5352966
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