Respuesta :

Answer:

11·699

Explanation:

Given the concentration of hydroxide ion in the solution is 5 × [tex]10^{-3}[/tex] M

Assuming the temperature at which it is asked to find the pH of the solution be 298 K

At 298 K the dissociation constant of water is [tex]10^{-14}[/tex]

∴ pH + pOH = 14 at 298 K

pOH of the solution = -log( concentration of hydroxide ion )

∴ pOH of the given solution = - log(5 × [tex]10^{-3}[/tex] = -0·699 + 3 = 2·301

   pH of the given solution = 14 - 2·301 = 11·699

∴ pH of the solution = 11·699                                  

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