Answer:
New volume = [tex]1.69\times 10^6[/tex] L
Explanation:
Using Charle's law
[tex]\frac {V_1}{T_1}=\frac {V_2}{T_2}[/tex]
Given ,
V₁ = [tex]1.27\times 10^6[/tex] L
V₂ = ?
T₁ = 11 °C
T₂ = 105 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (11 + 273.15) K = 284.15 K
T₂ = (105 + 273.15) K = 378.15 K
Using above equation as:
[tex]\frac{1.27\times 10^6}{284.15}=\frac{V_2}{378.15}[/tex]
[tex]V_2=\frac{1.27\times 10^6\cdot \:378.15}{284.15}[/tex]
New volume = [tex]1.69\times 10^6[/tex] L
