Answer:
P=1587.18 Pa
Explanation:
Given that
V= 1.77 L =1.77 x 10⁻³ m³
m = 0.226 g
Vrms= 178 m/s
We know that ideal gas equation
P V = n R T
[tex]n=\dfrac{m}{M}[/tex]
M=Molecular wight of the gas
P M = m R T -----------1
P=Pressure ,V=Volume ,n=Moles,R=Gas constant ,T=temperature
[tex]V_{rms}=\sqrt{\dfrac{3RT}{M}}[/tex] ------2
From above two equation we can say that
[tex]P=\dfrac{m}{V}\times \dfrac{V_{rms}^2}{3}[/tex]
[tex]P=\dfrac{0.266\times 10^{-3}}{1.77\times 10^{-3}}\times \dfrac{178^2}{3}[/tex]
P=1587.18 Pa
The pressure of the gas is 1587.18 Pa
