Answer: Yes the absorb in the visible range.
Explanation:
The relationship between wavelength and energy of the wave follows the equation:
[tex]E=\frac{Nhc}{\lambda}[/tex]
where,
[tex]E[/tex] = energy of the wave = 182 kJ/mol = 182000 J/mol
N = avogadro's number = [tex]6.023\times 10^{23}[/tex]
h = plank constant = [tex]6.6\times 10^{-34}Js^{-1}[/tex]
c = speed of light = [tex]3\times 10^8m/s[/tex]
[tex]\lambda [/tex] = wavelength of the wave = ?
Putting all the values:
[tex]182000=\frac{6.023\times 10^{23}\times 6.6\times 10^{-34}\times 3\times 10^8m/s}{\lambda}[/tex]
[tex]\lambda=0.65\times 10^{-6}m=650nm[/tex] [tex](1nm=10^{-9}m)[/tex]
The wavelength range for visible rays is 400 nm to 750 nm, thus the complex absorb in the visible range.
