Answer:
5
8
14
Step-by-step explanation:
1. [tex]4^{0} + 2 \times 3 - 2 = 1 + 6 - 2 = 5[/tex] (Answer)
{As we know that [tex]a^{0} = 1[/tex] for a ≠ 0}
2. [tex]2^{2} + 10 - 3 \times 2 = 4 + 10 - 6 = 8[/tex] (Answer)
{We know, [tex]a^{2} = a \times a[/tex]}
3. [tex]9 + 3^{2} - 1 \times 4 = 9 + 9 - 4 = 14[/tex] (Answer)
Note: When there is no brackets, we perform the operation of '×' and '÷' first and then we perform the operation of '+' or '-'
