Answer:
The kinetic energy is 0 J.
Explanation:
The kinetic energy of a relativistic proton is determined as follows:
KE = mc² - m₀c²
To determine m₀, we use the expression
E_rest = m₀c²
where
- E_rest is the rest energy
- c is the speed of light
- m₀ is the rest mass
Thus, rearranging the above expression we get
m₀ = E_rest/c²
=(0.15×10⁻⁹)/(3×10⁸)²
= 1.67×10⁻²⁷ kg
Therefore,
KE = (1.67×10⁻²⁷)(3×10⁸)² - (1.67×10⁻²⁷)(3×10⁸)²
= 0 J
